1. The graph of y = x2 is transformed to y = 2(x + 1)2 - 5. What is the turning point of the transformed graph?
The rule is in turning-point form y = a(x - h)2 + k. Since x + 1 = x - (-1), the turning point is (-1, -5).
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Practice functions, relations, algebra, calculus, probability, transformations, graphs, and mathematical modelling.
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The rule is in turning-point form y = a(x - h)2 + k. Since x + 1 = x - (-1), the turning point is (-1, -5).
Differentiate to get f'(x) = 3x2 - 6x + 4. At x = 2, f'(2) = 12 - 12 + 4 = 4.
Integrate 6x - x2 from 0 to 3: [3x2 - x3/3] from 0 to 3 = 27 - 9 = 18.
Set 100 = 250(0.5)t/12, so 0.4 = (0.5)t/12. Taking logarithms gives t = 12 log(0.4) / log(0.5) = 15.863..., so 15.9 years.
The unscaled total area is the integral from 0 to 3 of x(3 - x), which is 9/2. The unscaled area from 1 to 3 is 10/3. Hence P(X > 1) = (10/3)/(9/2) = 20/27.
The probabilities place 64 one standard deviation below the mean and 76 one standard deviation above it. The mean is (64 + 76)/2 = 70, and the standard deviation is 76 - 70 = 6.
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